一个铝球质量为27g,体积为20cm(三次方),已知铝的密度p铝=2.7×10(三次方)kg/m(三次方),通过计算问这铝球是否空心?
2023-04-27
问题描述:
一个铝球质量为27g,体积为20cm(三次方),已知铝的密度p铝=2.7×10(三次方)kg/m(三次方),通过计算问这铝球是否空心?最佳答案:
p铝 = 2.7×10³ kg/m³ = 2.7 g/m³
V铝 = m/p铝 = 27/2.7 = 10 cm³ <V = 20 cm³ ,空心
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